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First, we need to find which number when substituted into the equation will give the answer zero. \(f(1) = {(1)^3} + 4{(1)^2} + (1) - 6 = 0\) Therefore \((x - 1)\)is ...
If \((x \pm h)\) is a factor of a polynomial, then the remainder will be zero. Conversely, if the remainder is zero, then \((x \pm h)\) is a factor. Often, factorising a polynomial requires some ...
8d
Live Science on MSN'Dramatic revision of a basic chapter in algebra': Mathematicians devise new way to solve devilishly difficult equationsA polynomial is a type of algebraic equation that involves variables raised to a non-negative power — for example, x² + 5x + ...
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