Philadelphia Eagles running back Saquon Barkley will likely not play in the team’s final game of the season, meaning Eric Dickerson’s NFL single-season rushing record will remain safe.
Though Eric Dickerson said he didn't want Philadelphia Eagles running back Saquon Barkley to break his single-season rushing yards record, he hoped to
Eagles coach Nick Sirianni said running back Saquon Barkley 'probably' won't play Sunday, which would leave ex-Rams star Eric Dickerson's 2,105-rushing yard record intact.
Saquon Barkley is down to his final game to try to break Eric Dickerson’s season rushing record. The NFL rushing leader with 2,005 yards, Barkley is only 101 yards away from topping Dickerson’s
Philadelphia Eagles star Saquon Barkley is approaching a record held by Pro Football Hall of Fame running back Eric Dickerson. Barkley needs just 268 yards over the next two games to break a record held by Dickerson since 1984. Barkley is approaching 2,000 rushing yards on the season, which only two other players have accomplished since 2010.
Saquon Barkley wanted to hit the 2,000-yard mark in 16 games. Reaching that milestone had a special meaning for a running back that studies the history of the game.  Barry Sanders accomplished that feat,
Barkley and some other regular starters will rest vs. the Giants. Eagles coach Nick Sirianni said Howie Roseman, Jeffrey Lurie and others, including Barkley, were consulted.
Saquon Barkley appears set to sit out the Eagles' final regular-season game Sunday, denying the star his chance at breaking Eric Dickerson’s NFL single-season rushing record.
The Eagles opted for the smart play, keeping its top tailback healthy — and ensuring Dickerson’s rushing record hits a fifth decade.
Saquon Barkley is 101 yards away from breaking Eric Dickerson’s single-season record. Landon Dickerson said on WIP he wants Barkley to pursue it on Sunday for his "fairy tale ending."
Saquon Barkley might break Eric Dickerson's single-season rushing record in Week 18, but the Hall of Famer wants his storied mark to stand.